Asked by: Jorgelina Meredith
technology and computing programming languages

How do you avoid array index out of bound exception?

Last Updated: 25th May, 2020

In order to prevent "array index out of bound" exception, the best practice is to keep the starting index in such a way that when your last iteration is executed, it will check the element at index i & i-1, instead of checking i & i+1 (see line 4 below).

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Also know, what is array index out of bound exception?

The array index out of bounds error is a special case of the buffer overflow error. It occurs when the index used to address array items exceeds the allowed value. It's the area outside the array bounds which is being addressed, that's why this situation is considered a case of undefined behavior.

One may also ask, what causes ArrayIndexOutOfBoundsException? An ArrayIndexOutOfBoundsException is caused by trying to retrive a "box" that does not exist, by passing an index that is higher than the index of last "box", or negative.

  • name.
  • When accessing the contents of an array, position starts from 0.
  • When you loop, since i can be less than or equal to name.

Correspondingly, how do you handle an array out of bound exception in Java?

The index of an array is an integer value that has value in interval [0, n-1], where n is the size of the array. If a request for a negative or an index greater than or equal to size of array is made, then the JAVA throws a ArrayIndexOutOfBounds Exception. This is unlike C/C++ where no index of bound check is done.

What is String index out of bound exception in Java?

lang. StringIndexOutOfBoundsException if beginIndex is negative, or larger than the length of the string. This method returns a sub-string that begins with the character at the specified index and extends until the character at endIndex-1 index. It throws an java.

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