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Keeping this in consideration, what is the HVL of lead?
PENETRATION VALUES
Material | HVL (mm) | |
---|---|---|
30 keV | 60 keV | |
Tissue | 20.0 | 35.0 |
Aluminum | 2.3 | 9.3 |
Lead | 0.02 | 0.13 |
Thereof, how do you calculate half thickness?
The half-value layer formula is HVL = = 0.693/μ. Multiply your answer by 10 to express your HVL in millimeters. This is necessary because many attenuation coefficients are given with the units cm-1, and some HVLs are expressed in mm. Your answer can also be multiplied by 0.39 to convert centimeters to inches.
shield need to be about 13.8 feet of water, about 6.6 feet of concrete, or about 1.3 feet of lead. Thick, dense shielding is necessary to protect against gamma rays. The higher the energy of the gamma ray, the thicker the shield must be. X-rays pose a similar challenge.